How Much Does Dental Implant Cost in Indiana?
The average cost of dental implant in Indiana is $4,100 without insurance. With insurance, you can expect to pay around $1,435 — saving 65%.
Without Insurance
$4,100
With Insurance
$1,435
Medicare
$0
National Average
$3,500
Cost by City
| City | Without Insurance | With Insurance | Medicare |
|---|---|---|---|
| Indianapolis | $4,400 | $1,540 | $0 |
| Fort Wayne | $3,950 | $1,383 | $0 |
| Evansville | $3,900 | $1,365 | $0 |
Nearby States
How to Save
- 1. Ask for the cash/self-pay price — often 40-60% less than the billed price.
- 2. Compare prices between hospitals and freestanding centers.
- 3. Check if your insurance covers the procedure and what your copay will be.
- 4. Ask about payment plans or financial assistance programs.
- 5. Consider nearby states — prices can vary significantly across state lines.
Data sourced from American Dental Association Fee Survey 2025. Last updated: 2026-03-01. This information is for educational purposes only and does not constitute medical advice. This website is for informational purposes only and does not constitute medical advice. Always consult a qualified healthcare professional.